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seachen 发表于 2008-10-4 13:28

请问这个是什么错误？

[quote]MySQL server error report:Array ( [0] => Array ( [message] => MySQL Query Error ) [1] => Array ( [sql] => SELECT c.*, COUNT(s.cat_id) AS has_children FROM `jessonline_ec`.`ecs_category` AS c LEFT JOIN `jessonline_ec`.`ecs_category` AS s ON s.parent_id=c.cat_id GROUP BY c.cat_id ORDER BY parent_id, sort_order ASC ) [2] => Array ( [error] => MySQL server has gone away ) [3] => Array ( [errno] => 2006 ) ) MySQL server error report:Array ( [0] => Array ( [message] => MySQL Query Error ) [1] => Array ( [sql] => SELECT c.*, COUNT(s.cat_id) AS has_children FROM `jessonline_ec`.`ecs_category` AS c LEFT JOIN `jessonline_ec`.`ecs_category` AS s ON s.parent_id=c.cat_id GROUP BY c.cat_id ORDER BY parent_id, sort_order ASC ) [2] => Array ( [error] => MySQL server has gone away ) [3] => Array ( [errno] => 2006 ) [4] => Array ( [message] => MySQL Query Error ) [5] => Array ( [sql] => UPDATE `jessonline_ec`.`ecs_sessions` SET expiry = '1223021868', ip = '202.184.144.199', userid = '0', adminid = '0', data = 'a:0:{}' WHERE sesskey = '23b70c72903e9f32b2c5376d1889ca99' LIMIT 1 ) [6] => Array ( [error] => MySQL server has gone away ) [7] => Array ( [errno] => 2006 ) ) [/quote]

请问以上问题要怎么解决？

baoe 发表于 2008-10-4 22:18

你的数据库错误

Goda 发表于 2008-10-6 16:21

错误：MySQL server has gone away

解决方法：[url]http://faq.comsenz.com/?action-viewnews-itemid-130[/url]

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